Find the lowest natural number which when divided by 14,49,84 and 63 leaves a remainder 3 in each case
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Secondary School Math 10+5 pts
Find the lowest number which when divided by 14,49,84 and 63 leaves a remainder 3 in each case.
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Here is the solution:
We have to take L.C.M of all given numbers that are 14, 49, 84, and 63.
So, (L.C.M of 14, 49, 84, 63) = 1764
We also have remainder 3, so we need to add 3 to the L.C.M of numbers that is:-
Required number= (L.C.M of 14, 49, 84, 63) +3
= 1764+3=1767.
Therefore, the required number is 1767.
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