Find the lowest natural number which when divided by 15,20,25 and leaves a remainder 2 in each case
Answers
Answered by
0
Answer:
17
Step-by-step explanation:
15j2jzjdn÷15
so'ujd kdpam
Answered by
2
Answer:
You have to find LCM of 15, 20 and 25
It is 300
Add 2 to this number
300+2=302 is the answer
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