Question

Find the lowest natural number which when divided by 15, 25, 30 and 40 leaves
remainder 7 in each case:
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Answer 1

2 |20,30,40

2 |10,15,20

2 |5,15,10

5 |5,15,5

|1,3,1 Least Common Multiple of 20,30,40 is 120. remainder is given as 7.So answer is 120+7=127.

Answer 2

Step-by-step explanation:

lcm =5×5 ×3×2×2×2=600

lowest number is 600+7 = 607