find the lowest number between 200 and 500 which leaves a remainder 3 in each case when divided by 8 10 12 and 30
Answers
Answered by
3
Answer:
8,10,12,30 lcm =120
we to find number beetween 200 to 500.
then, 120x2=240
required number =240+3
=243 Ans
Similar questions