Find the lowest number difference between the two numbers 4 and diffence between their square is 32
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the two numbers at 6 and 2
let numbers = a and b
a - b = 4
a = b + 4 (i)
a^2 - b^2 = 32
(a+b) (a-b) = 32
substituting (i)
(2b + 4) (4) = 32
2b + 4 = 8
2b = 4
b = 2
a = b +4
a = 6
two numbers = 6 and 2
let numbers = a and b
a - b = 4
a = b + 4 (i)
a^2 - b^2 = 32
(a+b) (a-b) = 32
substituting (i)
(2b + 4) (4) = 32
2b + 4 = 8
2b = 4
b = 2
a = b +4
a = 6
two numbers = 6 and 2
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