Find the lowest number which leaves 3 as remainder when divided by
8, 12 and 16.
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Answered by
1
Answer:
I think 12 hope it helps sjsjzbjs
Answered by
2
Step-by-step explanation:
The L.C.M of 8, 12 and 16 is 48
So, the no which leaves remainder as 3 is (48+3)
(51 ×1) = 51
(51 2) =102
(51 3 ) =147
The least no. when divided by 7 is 147 without leaving no remainder
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