Question

Find the lowest number which when divided by 15, 16 and 21, leaves a remainder of 3 in each case.

Answer 1

Step-by-step explanation:

i don't understand your question

Answer 2

Answer:

Correct option is

B

235

12=2

2

×3

15=3×5

16=2

4

LCM=2

4

×3×5=240

Now, the number has a remainder of 7 when divided by 12. Similarly, number has remainder 10 on dividing by 15 and remainder is 11 when divided by 16. In each case, we are 5 short of getting a zero remainder. So the desired number must be 240−5=235

Option B