Question

Find the lowest number which when increased by 3 is. Divisible by 12,16 and 18​

Answer 1

Answer:

Step-by-step explanation:

We have to take LCM(Lowest Common Factor) of 12,16,18 which is 144.

Then we have to subtract it by 3 = 144-3=141

So therefore when we increase 141 by 3 which is 144 is divisible by 12,16,18.

Answer 2

Answer:

The lowest number is 144 and it is divisible by 12 , 16 and 18

Step-by-step explanation:

Given: Lowest number is increased by 3

To find: Lowest number which is divisible by 12, 16 and 18

Solution:

To find the LCM we have to use prime factorization method.

Multiples of 12 = 12, 24, 36, 48, 60, 72, 84, 96, 108, 120, 132, 144

Multiples of 16 = 16, 32, 48, 64, 80, 96, 112, 128, 144

Multiples of 18 = 18, 36, 54, 72, 90, 108, 126, 144,

LCM will be the common and uncommon factor

So LCM of 12 , 16 , and 18 is 144

Given that lowest number is increased by 3

Therefore we have to add 3 to this number

So the number is 144 + 3 = 147

So we can remove 3 from 147 then we get 144.

The number 144 is divisible by 12 , 16 , 18

Final answer:

The lowest number is 144 and it is divisible by 12 , 16 and 18

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