Question

Find the lowest number which when increased by 3 is. Divisible by 12,16 and 18

Answer 1

Here is you answer for the question

By finding the lcm of the three numbers we get

2*3*2*4*3

=144

the lowest number is 144-3

= 141

Hope it helps you

Answer 2

Answer is 141

Step-by-step explanation:

Get the prime factors of the number 12, 16 & 18

$12 = 2 \times 2 \times 316 = 2 \times 2 \times 2 \times 218 = 2 \times 3 \times 3$

• Get the distinct multiples: 2,2,2,2,3,3

Multiply them together $2 \times 2 \times 2 \times 2 \times 3 \times 3 = 144$

• Subtract 3

= 144-3 = 141