Question

find the
LSA and TSA of
cuboid whose 5.5 cm
b = 3.4
cm h = 2 cm​

Answer 1

AnsWer :

• TSA of Cuboid = 73 cm³
• LSA of Cuboid = 35.6 cm³

SolutioN :

Diagram :

$\setlength{\unitlength}{0.74 cm}\begin{picture}(12,4)\thicklines\put(5.6,5.6){ \tt{A} }\put(11.1,5.8){ \tt{B} }\put(11.08,8.9){ \tt{C} }\put(5.46,8.7){ \tt{D} }\put(3.55,10.15){ \tt{E} }\put(3.55,7.15){ \tt{F} }\put(9.14,10.235){ \tt{H} }\put(9.14,7.3){ G }\put(3.3,6.3){ \tt{3.4\:Cm} }\put(7.75,6.2){ \tt{5.5\:Cm} }\put(11.1,7.5){ \tt{2\:cm} }\put(6,6){\line(1,0){5}}\put(6,9){\line(1,0){5}}\put(11,9){\line(0,-1){3}}\put(6,6){\line(0,1){3}}\put(4,7.3){\line(1,0){5}}\put(4,10.3){\line(1,0){5}}\put(9,10.3){\line(0,-1){3}}\put(4,7.3){\line(0,1){3}}\put(6,6){\line(-3,2){2}}\put(6,9){\line(-3,2){2}}\put(11,9){\line(-3,2){2}}\put(11,6){\line(-3,2){2}}\end{picture}$

We have Formula :

$\tt \dagger \: \: \: \: \: TSA = 2( LB+BH+HL)$

$\tt \dagger \: \: \: \: \: LSA_{Cuboid }= 2( L + B)H$

Where as,

• L = 5 . 5 cm.
• B = 3 . 4 cm.
• H = 2 Cm.

Now,

$\tt \dagger \: \: \: \: \: TSA \: of \: Cuboid = 2( LB+BH+HL)$

$\tt : \implies TSA \: of C = 2( 5.5 \times 3.4 + 3.4 \times 2 + 2 \times 5.5)$

$\tt : \implies TSA \: of C = 2( 18.7+ 6.8+11)$

$\tt : \implies TSA \: of C = 2( 36.5)$

$\tt : \implies TSA \: of C = 73 \: c {m}^{3} .$

$\rule{90}2$

$\tt \dagger \: \: \: \: \: CSA_{Cuboid }= 2( L + B)H$

$\tt : \implies LSA_{Cuboid }= 2( 5.5 + 3.4)2$

$\tt : \implies LSA_{Cuboid }= 4( 8.9)$

$\tt : \implies LSA_{Cuboid }= 35.6c {m}^{3} .$

$\rule{90}2$

Answer 2

Step-by-step explanation:

CSA of cuboid is 35.6 CM sq.

TSA of cuboid is 73 cm sq.

CSA = 2*h(l+b)

=2*2(5.5+3.4)

=4*8.9

=35.6 CM sq.

TSA=2(l*b+b*h+h*l)

=2(5.5*3.4+3.4*2+2*5.5)

=2(18.7+6.8+11)

=2*36.5

=73 cm sq.

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