Math, asked by balmuripadmaja8, 2 months ago

find the Lsa of cubiod whose length, breath and height of are 2 cm× 3 cm× 1.5cm respective​

Answers

Answered by Anonymous
8

Answer:

⇒  Length of a cuboid (l)=8cm

⇒  Breadth of a cuboid (b)=7cm

⇒  Height of a cuboid (h)=4cm

⇒  Total surface area of cuboid =2(lb+bh+hl)          

                                                     =2(8×7+7×4+4×8)

                                                     =2(56+28+32)

                                                     =2(116)

                                                     =232cm2

∴  Total surface area of cuboid =232cm2

Step-by-step explanation:

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Answered by shaktisrivastava1234
20

 \huge   \underline{\red{\boxed{\bold{Correct \:  Question:}}}}

 \sf{Find \: the \: L.S.A. \: of \: cuboid \: whose \: dimension \: {is \: 2cm \times 3cm \times 1.5cm.}}

 \huge   \underline{\red{\boxed{\bold{Answer:}}}}

 \large \underline {\bf{Given}}

  \mapsto\sf{Length \:  of \:  cuboid \:  is   \: \bf{2cm.}}

  \mapsto\sf{Breadth \:  of \:  cuboid \:  is   \: \bf{3cm.}}

  \mapsto\sf{Height \:  of \:  cuboid \:  is   \: \bf{1.5cm.}}

 \large \bf \underline{To  \: find}

 \sf \leadsto{Lateral \:  surface  \: area(L.S.A.)  \: of  \: cuboid.}

 \large \bf \underline{Formula \:  required:}

  \underline{\blue {\boxed{ \sf{Lateral \:  surface  \: area (L.S.A.)  \: of \:  cuboid=2(length + breadth) \times height}}}}

 \large \bf \underline{According  \: to  \: Question:}

\sf{ \implies{Lateral \:  surface  \: area (L.S.A.)  \: of \:  cuboid=2(length + breadth) \times height}}

\sf{ \implies{Lateral \:  surface  \: area (L.S.A.)  \: of \:  cuboid=2(2 + 3) \times 1.5}}

\sf{ \implies{Lateral \:  surface  \: area (L.S.A.)  \: of \:  cuboid=2 \times 5\times 1.5}}

\sf{ \implies{Lateral \:  surface  \: area (L.S.A.)  \: of \:  cuboid=15 {cm}^{2} }}

 \large \underline{ \bf{Know  \: more:}}

 \boxed{ \begin{array}{|l|l|} \hline  \sf T.S.A  \: of  \: cuboid& \sf 2(lb+bh+hl) \\  \hline \sf Diagonal  \: of \:  cuboid&  \sf\sqrt{ {l}^{2}  +  {b}^{2}  +  {h}^{2} }  \\  \end{array}}

 \small \bf{Note:}

 \sf{Here,we \: use  \: {\bf{l}}, {\bf{b}} \: and  \: {\bf{h}} \: to \: represent \: length,}

  \sf{ {\bf{breadth}} \: and  \: {\bf{height}} \: of \: the \: cuboid.}

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