find the Lsa of the chalk box whose Length breadth and height are 16 cm 18 cm and 6 CM
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Step-by-step explanation:
Lsa=2l(h+b)
=2*(16)(18+6)
=32(24)
=768 sq.cm
Answered by
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Step-by-step explanation:
lsa of chak box (cubiod)= 2h (l+b)
then, = 2×6 (16+18)
= 18 (34)
= 612sqcm
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