Question

Find the M.I. of a uniform semicircular disc of mass 'M' and radius 'R' about an axis perpendicular to its plane and passing through point 'P' as shown.

Answer:
$m {r}^{2} ( \frac{9\pi - 16}{6\pi} )$

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Answer 1

M( 12L 2 + 4R 2) wil be the M.I of the problem.

Given:

L2=3R 2

To find: MI

Solution:

Geometry, the arm of arithmetic engaging attention the shape of individual objects, spatial friendships between differing objects, and the possessions of encircling scope. It is one of the most aged arms of arithmetic, bearing stood in answer to such efficient questions as those in the direction of scrutinizing, and allure name is arisen Greek words aim “Earth calculation.”

Eventually it was earned that arithmetic need not be restricted to the study of flat surfaces (plane arithmetic) and rigid three-spatial objects (dimensional arithmetic) but that an even ultimate abstract hopes and figures might be depicted and grown in the lines agreements

M.O.I of solid cylinder about its own axis =  

21 MR 2

M.O.I about an axis perpendicular to center of gravity =

M( 12L 2 + 4R 2)

M( 12L 2 + 4R 2) wil be the M.I of the problem.

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