Find the magnetic moment of Fe 3+ and Fe 2+
Answers
Answered by
5
heya it's Aastha...
spin only magnetic moment = n(n+2−−−−−−√
Fe3+ Z= 26= [Ar] 3d5, 4s0
the number of unpaired electrons (n)=5
so magnetic moment = 5(5+2)−−−−−−−√= 35−−√=5.91BM
similarly for Fe2+ configuration is [Ar] 3d6,4s0
the number of unpaired electrons =4
putting this value you can calculate the magnetic moment.
I hope it help you
spin only magnetic moment = n(n+2−−−−−−√
Fe3+ Z= 26= [Ar] 3d5, 4s0
the number of unpaired electrons (n)=5
so magnetic moment = 5(5+2)−−−−−−−√= 35−−√=5.91BM
similarly for Fe2+ configuration is [Ar] 3d6,4s0
the number of unpaired electrons =4
putting this value you can calculate the magnetic moment.
I hope it help you
princeranjanxhgsjcsk:
right ans yarr
itz right or not
right why?
nothing
from where u
gwalior
in which class
10
do have whataap
inbox m please
Similar questions