Find the magnetization of a bar magnet of length 10cm and cross-sectional area 4cm2 if the
magnetic moment is 2A - m2
nen
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1
Answer:
M
net
=2Am
2
,I=10cm=10×10
−2
m
Area of cross section = 4cm
2
=4×10
−4
m
2
Then,
Magnetization (M
z
)=
V
M
net
[V= l × cross-sectional area V=10×10
−2
×4×10
−4
V=4×10
−5
m
3
]
⇒M
z
=
4×10
−5
2
M
z
=5000
m
A
solution
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