Find the magnetizing field H and the magnetic flux density point of B at (a) a 105 mm from a long straight wire carrying a current of 15 A and (b) the center a 2000-turn solenoid which is 0.24m long and bears a current of 1.6A
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Distance of the point P from long wire = d = 105 mm = 0.105 m
i = 15 Amp
Magnetic Flux density (field) B due to a long straight wire carrying current i
B = μ i / (2πd)
= 4 π * 10⁻⁷ * 15 /(2 π 0.105) T
= 2.857 * 10⁻⁵ T
H = Magnetizing field = B /μ = 22.72 Amp/meter
===============
Solenoid:
Length L = 0.24 m
N = 2000 turns
n = turns/unit length = 2, 000/0.24 = 25, 000/3 per meter
i = current = 1.6 Amp
Magnetic field B (Flux density) due to a solenoid , inside the solenoid near the axis
B = μ n i = μ (N/L) i
B = 4 π * 10⁻⁷ * 25,000/3 * 1.6 A
= 1.675 * 10⁻² Tesla
H = Magnetizing field = B/μ = 40000/3 = 13, 333.3 Amp/meter
i = 15 Amp
Magnetic Flux density (field) B due to a long straight wire carrying current i
B = μ i / (2πd)
= 4 π * 10⁻⁷ * 15 /(2 π 0.105) T
= 2.857 * 10⁻⁵ T
H = Magnetizing field = B /μ = 22.72 Amp/meter
===============
Solenoid:
Length L = 0.24 m
N = 2000 turns
n = turns/unit length = 2, 000/0.24 = 25, 000/3 per meter
i = current = 1.6 Amp
Magnetic field B (Flux density) due to a solenoid , inside the solenoid near the axis
B = μ n i = μ (N/L) i
B = 4 π * 10⁻⁷ * 25,000/3 * 1.6 A
= 1.675 * 10⁻² Tesla
H = Magnetizing field = B/μ = 40000/3 = 13, 333.3 Amp/meter
kvnmurty:
:-)
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