Question

Find the magnetude of velocity A=32+2j+4k is

Answer 1

Answer:

$A = \sqrt{ ({32})^{2} + ( {2})^{2} + ( {4})^{2} } \\ = \sqrt{1024 + 4 + 16} = \sqrt{1044} \\ = 2 \times 3 \sqrt{29} \\ = 6 \sqrt{29} \\ \red{ \boxed{ \purple{ \huge\star Magnitude \: of \: vector \:A = 6 \sqrt{29} }}}$

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