find the magnification of the convex lens object of height 9cms and the image height is 36cms
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Answer:
Magnification of image is, ∣m∣=2 as image size (h
′
) is double the object size (h)
Thus, m=±2
as for a less, m=
u
v
(object distance =u , image distance =v)
⇒
u
v
=±2 ⇒v=2u or v=−2u
(i) case I : v=2u⇒u=v/2 then by lens formula,
v
1
−
u
1
=
f
1
⇒
v
1
−
v
2
=
20
1
⇒v=−20 cm
(ii) case II : when v=−2u⇒u=−v/2, so
v
1
−
u
1
=
f
1
⇒
v
1
+
v
2
=
20
1
⇒v=20/3 cm
∴ Image distance can be 20 cm (if image is virtual) on can be 20/3 cm (if image is real)
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