Find the magnitude and direction in a semi circle of radius 0.5 cm carrying a current of 2A which placed in a uniform magnetic field 0.3T
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Answer:
Given
n=50turns, R=0.5m, I=5A,
According to Bio-sawart Law
magnetic flux density is given by B
⇒B=
2R
μ
0
nI
⇒B=
2×0.5
4π×10
−7
×50×5
=3.14×10
−3
T
Explanation:
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