Question

find the magnitude and direction of an electric field from point P.​

Answer 1

Answer:

1. Point P is on the left of Q1. The test charge is positive and Q1 is positive so that the direction of an electric field to leftward. The test charge is positive and Q2 is negative so that the direction of an electric field to rightward. Distance between Q2 and point P (r2P) = 3 + a = 3 – 1.8 = 1.2 cm.

Explanation:

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