Question

Find the magnitude and direction of resultant of two force 30N and 60N after on a body with the angle of 120°​

Answer 1

answer: Just denote the intersection of the forces at the origin, for simplicity. Align force F⃗ B with the horizontal. Then:

F⃗ A=20(cosπ3x^+sinπ3y^)

F⃗ B=30(x^+0y^)

Adding them up is simple:

F⃗ net=F⃗ A+F⃗ B=40x^+103–√y^

From this, one can get the magnitude and direction by definition. For a vector v⃗ =ax^+by^ , we have

|v⃗ |=a2+b2−−−−−−√

and

tanθ=ba

explaination:

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