FIND THE MAGNITUDE AND DIRECTION OF THE RESULTANT OF THE FOLLOWING VECTORS. A) A 10N FORCE POINTING NORTH AND PERPENDICULAR TO A 6N FORCE POINTING WEST. B) TWO 15N FORCES POINTING EAST AND SOUTH RESPECTIVELY WITH A PERPENDICULAR ANGLE BETWEEN THEM.
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Answered by
1
Answer:
The resultant force acts due north.
⇒ The horizontal components of the two forces cancel
⇒ 10=Psin30=
2
P
=10⇒P=20N
∴ Resultant R=Pcos30=20×
2
3
=10
3
N.
Answered by
1
Answer:
The resultant force acts due north.
⇒ The horizontal components of the two forces cancel
⇒ 10=Psin30=
2
P
=10⇒P=20N
∴ Resultant R=Pcos30=20×
2
3
=10
3
N.
Explanation:
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