Question

find the magnitude in a triangle angle ABC, angle b =90°,angle c =35°,<a=? ​

Answer 1

Answer:

Step-by-step explanation:

formula of magnitude of a triangle is $A^{2} +B^{2} =C^{2}$

SO here it is $90^{2} +35^{2} = a^{2} \\ie,( \sqrt{90^2} + \sqrt{35^2} = <a$