find the magnitude of a charge that can be moved from infinity to a point in an electric field work the potential is 20 volt by spending 600 joule of work
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Answered by
3
we know that
v=work /charge
20v=600/q
charge=1/30
v=work /charge
20v=600/q
charge=1/30
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Answered by
4
Hi....
WKT
Work done = potential difference / charge
Thus charge(Q) = potential difference(V) / work done (WD)
Q = 20 / 600
Q= 0.03 C..
Hope this helps u!!
WKT
Work done = potential difference / charge
Thus charge(Q) = potential difference(V) / work done (WD)
Q = 20 / 600
Q= 0.03 C..
Hope this helps u!!
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