Question

Find the magnitude of A, if A = 16i^ + 21j^.No spams.​

Answer 1

The magnitude of A

= square root of 16 square + 21 square

= square root of 256 + 441

= square root of 697.

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Answer 2

(16^ 2 + 21^ 2)^ 1/2

= (256 + 441)^ 1/2

= (697)^ 1/2.

= $\sqrt{697}$

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