Question

find the magnitude of a P vector is equal to 3 ICAP + 4 j cap​

Answer 1

Answer:

P = 5

Explanation:

given a vector

P = 3i + 4 j

magnitude of a vector can be calculated as

A = ai + bj + ck  

then

magnitude of A = √a² + b² + c²

so from this we can calculate

P = √3²+4²

P = √9+16

P = √25

P = 5

Answer 2

Answer:

The magnitude of a vector P=3i+4j is 5unit

Explanation:

• A vector is a physical quantity described by both magnitude and direction

• The component form of a vector is given by the formula

        $A=ai+bj+ck$

        where $a,b,c$ are components along X, Y, Z axes

        $i,j,k$ are unit vectors along X, Y, Z axes

• The magnitude of that vector can be calculated as $/A/=\sqrt{a^{2} +b^{2} }$

From the question, we have

the component force of the vector $P=3i+4j$

as compared to the above equation

$a=3 \\b=4$

now the magnitude of the vector $/P/=\sqrt{3^{2} +4^{2} } =5$ unit