Find the magnitude of an angle which is 2/3 of its supplement
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Let angle be x
Its supplement vl be 90-x
According to Q's
X=2/3(90-x)
3x=2(90-x)
3x= 180-2x
5x= 180
X= 36
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Answer:
Step-by-step explanation:
Let the first angle be `x`
Then the other angle will be 2/3 of x = 2x/3
According to the question
⇒x + 2x/3 = 180 [supplementary]
⇒(3x+2x)/3 = 180
⇒5x = 180 ×3
⇒x = 540/5
∴x= 108°
∴The required angle = 2x/3
= 2(108)/3
= 216/3
= 72°
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