Question

Find the magnitude of angle A
if 2(sin)²A−3sin A+1=0​ 
​

Answer 1

$2 {sin}^{2} \alpha - 3 \sin \alpha + 1 = 0 \\ \\ 2 { \sin }^{2} \alpha - 2 \sin\alpha - \sin \alpha + 1 = 0 \\ \\2 \sin \alpha ( \sin \alpha - 1) - 1( \sin \alpha - 1) = 0 \\ \\ (2 \: sin \alpha - 1)(sin \alpha - 1) = 0 \\ \\ sin \alpha = \frac{1}{2} \\ \\ sin \alpha = 1 \\ \\ \alpha = {30}^{0} \\ \\ \alpha = {90}^{0}$

hope it helps

Answer 2

Answer:

Step-by-step explanation: