Find the magnitude of angle A if tan- 2cosAtanA+2cosA=1
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Step-by-step explanation:
ANSWER
tanA−2cosAtanA+2cosA−1=0
cosA
sinA
−2cosA⋅
cosA
sinA
+2cosA−1=0
cosA
sinA−2sinAcosA+2cos
2
A−cosA
=0
sinA−2cosA(sinA−cosA)−cosA=0[cosA
=0]
(sinA−cosA)−2cosA(sinA−cosA)=0
(sinA−cosA)(1−2cosA)=0
∴sinA−cosA=0 or (1−2cosA)=0
sinA=cosA⟹
cosA
sinA
=1
tanA=1⟹
A=45
0
1−2cosA=0
2cosA=1⟹cosA=
2
1
∴
A=60
0
pls follow
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