Question

find the magnitude of charge present in 2.4g Mg2+

Answer 1

Answer:

9600 C

Explanation:

one one mole of magnesium is 24 grams so the number of moles present in 2.4 grams is 0.1.

so the number of atoms present is

6×10²³×0.1 =6×10²².

each atom has 2 + charge which is is 1.6×10^-19 C.

so charge present in in 2.4 grams is

6×10³×1.6C=9600C.