Science, asked by vedant3452, 5 months ago

Find the magnitude of current flowing through 12 resistance and potential difference across 4 ohm​

Answers

Answered by gursharans886
0

Answer:

I=RV=88=1A. Hence, the current flowing through the resistor R1 (4 ohms) is 1A. Now the power dissipated in the resistor R1 (4 ohms) is given as follows. P=I2R=12×4=1×4=4W.

Explanation:

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