Question

find the magnitude of current flowing through 12w resistance and potential difference across 4w​

Answer 1

Step-by-step explanation:

The circuit can be reduced, step by step, to a single equivalent resistance. The 8 ohm and the 8 ohm are connected in parallel , and so they can be replaced by an equivalent resistor Rp of 4 ohms, using the below equation.

Rp=(8+8)(8×8)=4ohms

This resistor is connected in series with the 4 ohm resistor R1. The total resistance Rt of the circuit is then

Rt =R1+Rp=4+4 = 8 ohms.

Since the 4 ohm and the 4 ohm are connected in series, they have the same current I1, which must be equal to the current of the battery. Using Ohms law we get,

I=RV=88=1A.

Hence, the current flowing through the resistor R1 (4 ohms) is 1A.

Now the power dissipated in the resistor R1 (4 ohms) is given as follows.

P=I2R=12×4=1×4=4W.