Question

Find the magnitude of each of the interior angles of a regular Pentagon, Octagon, polygon of 12 sides

Answer 1

Answer:

Magnitude of interior angle of a

regular Pentagon is 108°,

regular octagon = 135°

polygon of 12 sides = 150°

Explanation:

Formula for finding interior angle of any polygon having sides n = ( n - 2 ) × 180°

Interior angle of a Pentagon =( 5 - 2) × 180°

= 3 × 180°

= 540°

Magnitude of each angle = 540° ÷ 5 = 108°

For octogon ( 8 sides) = (8 -2) ×180° = 6× 180 =1080°

Magnitude of each angle =1080÷8=135°

For polygon with 12 sides = (12-2)×180° =10×180°=1800°

magnitude of each angle = 1800°÷12=150°