Find the magnitude of momentum of a body of mass 10kg moving with a velocity of
5m/s.
locs bod
1) 40kgm/s
2) 30kgm/s
C) 50kgm/s
D) 60kgm/s
Answers
Answered by
4
For a perfectly elastic collision, coefficient of restitution is e=1.
Let u and v be the velocities of 10 kg and 1 g masses after collision.
Thus, e=
rel. vel. of approach
rel. vel.of separation
=
5−0
v−u
=
5
v−u
But, as e=1, we have v−u=5.
Total momentum before collision is P=10×5=50 kg m/s
Total momentum after collision is P=10×(v−5)+0.001×v=10.001v−50
Thus, 10.001v−50=50⇒v=
10.001
100
≈10 m/s
Let u and v be the velocities of 10 kg and 1 g masses after collision.
Thus, e=
rel. vel. of approach
rel. vel.of separation
=
5−0
v−u
=
5
v−u
But, as e=1, we have v−u=5.
Total momentum before collision is P=10×5=50 kg m/s
Total momentum after collision is P=10×(v−5)+0.001×v=10.001v−50
Thus, 10.001v−50=50⇒v=
10.001
100
≈10 m/s
Answered by
6
Answer:
option C) 50kgm/s
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