Find the magnitude of the force between two charges of 1.0 c each which are 1.0 meter apart?
Answers
use the formula U=1/4π∈
=9×10∧9 Nm²/c²
Given,
The magnitude of two charges = 1 C each
Distance between the two separated charges = 1 meter
To find,
The magnitude of the force between the two charges.
Solution,
We can simply solve this numerical problem by using the following process:
Mathematically,
The magnitude of the force between two charges Q and q, separated by a distance of R units, respectively, is equal to;
|F| = k × Qq/R^2,
where k = constant of proportionality
= 1/(4π×epsilon)
= 8.988 × 10^9 Nm^2/C^2
Now, according to the question;
The magnitude of the force between the two given charges
= |F| = k × Qq/R^2
= (8.988 × 10^9 Nm^2/C^2) × (1C)^2/(1m)^2
= 8.988 × 10^9 N
=> |F| = 8.988 × 10^9 N
Hence, the magnitude of the force between the two given charges is equal to 8.988 × 10^9 N.