Physics, asked by masstsg, 1 month ago

Find the magnitude of vector 3^i − 2^j + √3k ?​

Answers

Answered by whyhowsharma281
0

Method of solving:

Take the square root of the sum of square of every vector.

Answer:

 \sqrt{9  + 4 + 3}

Which will result into √16 = 4

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Answered by gopika1akipog
0

Explanation:

magnitude of vector 3^i − 2^j + √3k

=√3²+(-2)²+(√3)²

=√9+4+3

=√16

=√4²

=4

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