Find the magnitude of vector 3^i − 2^j + √3k ?
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Method of solving:
Take the square root of the sum of square of every vector.
Answer:
Which will result into √16 = 4
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Explanation:
magnitude of vector 3^i − 2^j + √3k
=√3²+(-2)²+(√3)²
=√9+4+3
=√16
=√4²
=4
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