Question

find the magnitude of vector A=4i+6j​

Answer 1

Answer:

Magnitude of vector A=4i+6j​ is 2√13.

Explanation:

Given,

Vector A=4i+6j​

To find: the magnitude of vector A=4i+6j​

Solution:

For a vector, V = xi +yj,

Magnitude is given as :

$|V| = \sqrt{x^2 + y^2}$

here, x = 4,y = 6

So, Magnitude of vector will be:

$| A| = \sqrt{4^2 + 6^2}\\\\|A| = \sqrt{16 + 36}\\\\|A| = \sqrt{52}\\\\|A| = 2\sqrt{13}$

Therefore, Magnitude of vector A=4i+6j​ is 2√13.