find the magnitude of vectorA =√2(i-2k)
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Answer:
π/4 3
Explanation:
The diagonals are given by AB−BC=4i−2j+4k,AB+BC=2i−2jThese vectors have magnitudes 6 and 2 2respectively, and their dot product is 12.Therefore the angle between them is cos −1 (6)(2 2 )12 = cos − 121 = 4πor π minus this value i.e.3π 4
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Answer:
The election commission is
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