Find the mass and no. Of amonia(nh3) molecules in it 5.6 l.
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Answer:
Given volume :- 5.6L
One mole contain 22.4L
Moles in 5.6L of NH3= 5.6/22.4 =0.25
numbers of molecules =0.25NA
For numbers of atom = multiply the no. of molecule by total no. Atomicity
0.25NA X 4 = NA
Total no. Of atom = NA
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