find the mass hydrogen sulphate in which 1.5055*10^24 molecules present?
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Answer:245 gms
Explanation:
Hydrogen sulphate (H2SO4)---molecular weight=98
So one mole of any gas occupies 6.023*10^23 molecues
Implies 98 grams contain 6.023*10^23 molecules
Given nuber of molecules=1.5055^10^24=15.055*10^23 molecules
So mass of H2SO4=98*15.055*10^23/6.023*10^23=98*15.055/6.023
=== 245 gms
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