Find the mass in grams of 1.00 x 1023 molecules of h2s
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no of mole of H2S = no of molecules /Avogadro's constant
= 1 × 10²³/6.023 × 10²³
= 1/6.023
we know,
mole = given wt /molecular wt
1/6.023 = given wt/34
given wt = 34/6.023 = 5.645
hence, weight of H2S = 5.645 g
= 1 × 10²³/6.023 × 10²³
= 1/6.023
we know,
mole = given wt /molecular wt
1/6.023 = given wt/34
given wt = 34/6.023 = 5.645
hence, weight of H2S = 5.645 g
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