find the mass in grams of 88.4 moles of NI3? given the molar mass of N = 14.01 g/mol and I = 126.90 g/mol
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mass of NI₃ in grams is 34892.364 g
it has given that 88.4 moles of NI₃.
we have to find the mass in grams of NI₃ where the atomic mass of N = 14.01 g/mol and I = 126.90 g/mol.
molar mass of NI₃ = atomic mass of N + 3 × atomic mass of I
= 14.01 + 3 × 126.90
= 14.01 + 380.70
= 394.71 g/mol
we know, mole = given mass/molecular mass
⇒88.4 = given mass/394.71
⇒given mass = 88.4 × 394.71
= 34,892.364 g
therefore, mass of NI₃ in grams is 34892.364 g
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