Question

find the mass, no.of formula units and no. of constituent atoms in 0.5 moles of ammonium carbonate.​

Answer 1

Answer:

Explanation:

Moles of (NH4)2CO3 = 0.5 mol

Molar mass = 96.09 g/mol

Mass = moles  * molar mass

          = 0.5 × 96.06

          48.03 g

Molecules = 0.5 × Na

                 = 3.011×10∧23 molecules

No of atoms = molecules × atomicity (number of atoms in mole of(NH4)2CO3)

                  = 3.011×10∧23 × 10

                   = 3.011×10∧24 atoms