find the mass of 0.5 mole of Na2CO3
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Answered by
22
molecular mass of Na,C and 0 are respectively 23u, 12u and 16u respectively.
so mass of 2*Na=2*23=46u
mass of 3*O=3*16=48u
so molecular mass of Na2CO3=46u+12u+48u
=106u
so mass of 1 mole of Na2CO3=106gms
so mass of 0.5 mole of Na2CO3=0.5*106gms
=53gms
hence mass of 0.5 mole of Na2CO3 is 53gms.
so mass of 2*Na=2*23=46u
mass of 3*O=3*16=48u
so molecular mass of Na2CO3=46u+12u+48u
=106u
so mass of 1 mole of Na2CO3=106gms
so mass of 0.5 mole of Na2CO3=0.5*106gms
=53gms
hence mass of 0.5 mole of Na2CO3 is 53gms.
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