Find the mass of 1.12L of C02
Answers
Answer:
2l
Explanation:
Let the formula of hydrocarbon be C
a
H
b
.
C
a
H
b
+[a+(b/4)]O
2
→aCO
2
+(b/2)H
2
O
∵ 22.4 litres of C
a
H
b
gives on combustion = 44a g CO
2
∴ 1.12 litres of C
a
H
b
will give on combustion =
22.4
44a×1.12
=2.2ag.
∴2.2a=2.2∴a=1
Similarly,
∵ 22.4 litres of C
a
H
b
gives = 18×(b/2)gH
2
O
∴ 1.12 litres of C
a
H
b
gives = 18×
2
b
×
22.4
1.12
gH
2
O=
40
18×b
gH
2
O
∴1.8=(
40
18
)×b∴b=4
∴ Hydrocarbon is CH
4
Thus, mass of hydrocarbon taken = (16×1.12)/22.4=0.8g
Also, O
2
used for combustion of 16 g CH
4
=
4
(a+b)
=2 mol
= 2×22.4litre
∴O
2
used for combustion of 0.8 g. CH
4
=
16
2×22.4×0.8
=2.24litre
Nearest integer is 2 L.
Answer:
2.2gm
Explanation:
no. of mole at stp = volume in liter/22.4 liter
then no of mole of CO2 = 1.12/22.4 = 1/20
Mole = Given mass/Molar Mass
1/20 = Given mass/44 (molar mass of CO2=44)
Given mass= 1/20×44 =2.2 gm