Question

find the mass of 10 cm cube of a gas at STP if the rms speed of gas molecules is 400 m/s​

Answer 1

Answer:

oxygen gas = 1 cm 3 = 10-3 m 3 (Given) Volume of oxygen gas at STP= 22.4L = 22.4 x 10 3 cm 3. we know, ideal equation for gas: n = PV/RT = [1x1x10-3]/[0.082×273] = 10-3 /22.4. Now, mass = [10-3 /22.4] x 32 grams = 1.428 x 10-3 grams = 1.428 mg. Question 5: Equal masses of air are sealed in two vessels,

Explanation: