Find the mass of 100 molecules of chlorine .
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Answer:
This problem is a classic stoichiometry problem. To solve this problem, you want to have your periodic table (to find the molar mass (g/mol) of Cl2), calculator, and Avogadro's number handy. The approach is outlined below:
39.2 " g Cl2" ((1 " mole of Cl2")/(70.9 " g Cl2"))((6.022 * 10^23 "molecules Cl2")/(1 " mole Cl2")) = 3.33 * 10^23 " molecules Cl2"
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Answer:
1000 molekyules = 6 + 10 ^44 atms=mass= 10^-21 grams
Explanation:
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