find the mass of 5 mol of calcium carbonate
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Atomic mass of Ca= 40 u Atomic mass of C=12 u Atomic mass of O= 16 u Therefore, molecular mass of 5 moles of CaCO3= 5×(40×1)+(12×1)+(16×3)= 5×(40+12+48)= 5×100 = 500 g
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