Find the mass of a car that has a speed of 30 m/s and a momentum of 45,000 kg*m/s
Answers
Answer:
Given,
Given,Final velocity, v=0
Given,Final velocity, v=0Initial velocity, u=30ms
Given,Final velocity, v=0Initial velocity, u=30ms −1
Given,Final velocity, v=0Initial velocity, u=30ms −1
Given,Final velocity, v=0Initial velocity, u=30ms −1 Force = mass x acceleration
Given,Final velocity, v=0Initial velocity, u=30ms −1 Force = mass x accelerationF=ma
Given,Final velocity, v=0Initial velocity, u=30ms −1 Force = mass x accelerationF=maa=F/m=−5000/1000=−5ms
Given,Final velocity, v=0Initial velocity, u=30ms −1 Force = mass x accelerationF=maa=F/m=−5000/1000=−5ms −2
Given,Final velocity, v=0Initial velocity, u=30ms −1 Force = mass x accelerationF=maa=F/m=−5000/1000=−5ms −2
Given,Final velocity, v=0Initial velocity, u=30ms −1 Force = mass x accelerationF=maa=F/m=−5000/1000=−5ms −2 From the First equation of motion,
Given,Final velocity, v=0Initial velocity, u=30ms −1 Force = mass x accelerationF=maa=F/m=−5000/1000=−5ms −2 From the First equation of motion,v=u+at
Given,Final velocity, v=0Initial velocity, u=30ms −1 Force = mass x accelerationF=maa=F/m=−5000/1000=−5ms −2 From the First equation of motion,v=u+at0=30+(−5t)
Given,Final velocity, v=0Initial velocity, u=30ms −1 Force = mass x accelerationF=maa=F/m=−5000/1000=−5ms −2 From the First equation of motion,v=u+at0=30+(−5t)0=30−5t
Given,Final velocity, v=0Initial velocity, u=30ms −1 Force = mass x accelerationF=maa=F/m=−5000/1000=−5ms −2 From the First equation of motion,v=u+at0=30+(−5t)0=30−5t5t=30
Given,Final velocity, v=0Initial velocity, u=30ms −1 Force = mass x accelerationF=maa=F/m=−5000/1000=−5ms −2 From the First equation of motion,v=u+at0=30+(−5t)0=30−5t5t=30t=30/5
Given,Final velocity, v=0Initial velocity, u=30ms −1 Force = mass x accelerationF=maa=F/m=−5000/1000=−5ms −2 From the First equation of motion,v=u+at0=30+(−5t)0=30−5t5t=30t=30/5t=6
Given,Final velocity, v=0Initial velocity, u=30ms −1 Force = mass x accelerationF=maa=F/m=−5000/1000=−5ms −2 From the First equation of motion,v=u+at0=30+(−5t)0=30−5t5t=30t=30/5t=6Hence, after6sec car will stop.
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