Physics, asked by jb9471, 7 hours ago

Find the mass of a car that has a speed of 30 m/s and a momentum of 45,000 kg*m/s

Answers

Answered by JiaKher1
2

Answer:

Given,

Given,Final velocity, v=0

Given,Final velocity, v=0Initial velocity, u=30ms

Given,Final velocity, v=0Initial velocity, u=30ms −1

Given,Final velocity, v=0Initial velocity, u=30ms −1

Given,Final velocity, v=0Initial velocity, u=30ms −1 Force = mass x acceleration

Given,Final velocity, v=0Initial velocity, u=30ms −1 Force = mass x accelerationF=ma

Given,Final velocity, v=0Initial velocity, u=30ms −1 Force = mass x accelerationF=maa=F/m=−5000/1000=−5ms

Given,Final velocity, v=0Initial velocity, u=30ms −1 Force = mass x accelerationF=maa=F/m=−5000/1000=−5ms −2

Given,Final velocity, v=0Initial velocity, u=30ms −1 Force = mass x accelerationF=maa=F/m=−5000/1000=−5ms −2

Given,Final velocity, v=0Initial velocity, u=30ms −1 Force = mass x accelerationF=maa=F/m=−5000/1000=−5ms −2 From the First equation of motion,

Given,Final velocity, v=0Initial velocity, u=30ms −1 Force = mass x accelerationF=maa=F/m=−5000/1000=−5ms −2 From the First equation of motion,v=u+at

Given,Final velocity, v=0Initial velocity, u=30ms −1 Force = mass x accelerationF=maa=F/m=−5000/1000=−5ms −2 From the First equation of motion,v=u+at0=30+(−5t)

Given,Final velocity, v=0Initial velocity, u=30ms −1 Force = mass x accelerationF=maa=F/m=−5000/1000=−5ms −2 From the First equation of motion,v=u+at0=30+(−5t)0=30−5t

Given,Final velocity, v=0Initial velocity, u=30ms −1 Force = mass x accelerationF=maa=F/m=−5000/1000=−5ms −2 From the First equation of motion,v=u+at0=30+(−5t)0=30−5t5t=30

Given,Final velocity, v=0Initial velocity, u=30ms −1 Force = mass x accelerationF=maa=F/m=−5000/1000=−5ms −2 From the First equation of motion,v=u+at0=30+(−5t)0=30−5t5t=30t=30/5

Given,Final velocity, v=0Initial velocity, u=30ms −1 Force = mass x accelerationF=maa=F/m=−5000/1000=−5ms −2 From the First equation of motion,v=u+at0=30+(−5t)0=30−5t5t=30t=30/5t=6

Given,Final velocity, v=0Initial velocity, u=30ms −1 Force = mass x accelerationF=maa=F/m=−5000/1000=−5ms −2 From the First equation of motion,v=u+at0=30+(−5t)0=30−5t5t=30t=30/5t=6Hence, after6sec car will stop.

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