Find the mass of a hollow sphere of copper having internal and external diameters of
9 cm and 10 cm respectively, given 1 cm^3 of copper has a mass of 8.82 g.
Answers
Answer:
9+10+1+3+8.82=31.82 answer
Answer:
1251.52g
Step-by-step explanation:
First find the volume of the whole sphere. Then find the volume of the hollow part inside. The difference of the two volumes is the volume of the copper used. With that information, we will then find the mass of the copper used.
Find the volume of the sphere with dimeter of 10 cm:
Volume of the sphere = 4/3 πr³
Volume of the sphere = 4/3 π (10 ÷ 2)³
Volume of the sphere = 500/3 π cm³
Find the volume of the sphere with dimeter of 9 cm:
Volume of the sphere = 4/3 πr³
Volume of the sphere = 4/3 π (9 ÷ 2)³
Volume of the sphere = 243/2 π cm³
Find the volume of the copper used:
Volume of copper used = 500/3 π - 243/2 π
Volume of copper used = 271/6 π cm³
Find the mass:
1 cm³ = 8.82g
271/6 π cm³ = 8.82 x 271/6 π
271/6 π cm³ = 1251.52
Answer = 1251.52g